So what to do today (2012-10-22)?
Start with understanding the
situation.
As opposing rings gain
velocity transverse to the plane of the rings, the two rings' tendency to Axis alignment
pulls away from each other, leading to a tendency to return to
parallel. At velocity .707c, the Axis effect may be 0, but then
increase again as velocity increases then reduces to 0 again at c.
Moving pulls neutrinos apart in the old Model.
What can neutrinos teach
us? What can we learn from neutrinos? The second question is
different from the first, but hopefully we are open to learning so
the second is a very large subset of the first.
Neutrinos exist. They
travel at the speed of light and probably slower as well. They go
through matter with very little effect. They have very little or no
charge. They have very little magnetic moment. The last two are
probably precisely why they go through matter.
How to create a picture
of neutrinos that works in the mnp Model? Or is it time to
abandon the Model? Well, the second step after understanding the
situation is to figure out what could be. Ergo,
Brainstorm.
What are the
possibilities, implausibilities, and impossibilities?
Idea:
|
Comment:
(usually added later)
|
Opposing rings
|
cannot travel as any kind of unit
|
Ring of one charge
|
unbalanced charge, though may be small
|
Opposing coils
|
problems "getting back" when traveling
|
Coils not flat but vertical
|
|
Coils in a torus ("doughnut" to you
Simpson fans)
|
|
Wound strands moving opposite
|
getting back, same travel difficulties as rings
|
Opposing charge moving same direction
|
may make bigger coils
|
If electrons are to be believed, coils are
natural once started
|
|
Figments have a movement direction as a third
attribute
|
Ugh
|
How could n and p
filaments traveling the same direction be kept together. At
parallel, they have no
influence on each other but if they wobble, they will
start to repel. That implies something keeps them
together.
|
|
Multiple strands, for example 2n and 1p
|
|
Different diameters
for n and p figments, so filaments of one travel inside the
other.
|
I don't like this, but it might lead to a left
hand preference as in the decay of cobalt-60 and a prevalence of
protons and electrons in this solar system or galaxy.
|
A coil like a
solenoid, with a few coils stretched to return back where the
coil sticks out a
little from the other charge coil, which also heads back
through free space in the center
|
travel issue
|
Simple rings interlocked at 90 degrees
|
travel much above .707c would lead to flattening
and crossing at 2 points.
|
Twenty five minutes
later, I start the second page of notes:
Two strands linear
going and 2 strands returning from two collections of coils
(rather like the quark bulbs of 2011)
|
strands must be separated or they conflict
|
Coils as fundamental, looping back on opposite
sides?
|
v=c looks ugly
|
Single filament of mixed n's and p's
|
Ouch - how does a filament maintain stability at
the interface between n and p?
|
For travel, the filaments want to go the same
direction.
|
Make that have to. Deal with it.
|
How about two filaments of each type, a cross in
cross section.
|
A little complicated, but what would that take?
|
Side notes: Most of the
value judgments here were added after the list was "complete."
I do not like to stop the flow of ideas with loud NO's.
When is a list complete?
Either when we run out of ideas completely, or the flow of ideas has
slowed greatly and an idea looks promising.
Fortunately, the last
idea did look promising. As ASCII art, the cross section:
n
p+p
n
where the + is just a
logical "center" for the four filaments. Or
n
p
x
p
n
And we can go on to step
three.
Evaluate.
Neutrinos as Two Pairs of
Charge Structure Filaments
With a matched pair of
n-filaments across the diagonal of a square attracting each other by
Axis alignment and Travel alignment, the other matched pair of p-filaments attracting
each other by Axis and Travel. The adjacent mis-matched filaments attract
by Travel but repel by Axis. Could that be balanced to be stable?
The first crude "effect"
calculation in cross section suggests t (travel alignment effect)
from 3 filaments plus the axis alignment of the single matching
filament must be stronger than the axis alignment repulsion from the
closer two, opposite filaments. The net repulsion is 2/sqrt(2) of the
direct repulsion from one opposite filament. Use d as the distance
between opposing filaments, so sqrt(2)d the distance to the far
filament.
Oh, but remember that the
filaments are REALLY close and overlap. If the effect strength is
inversely proportional to distance between the figments, going to 0
at 2r, and the filaments are as close as their Separation will
"normally allow" in a steady state, all effects will be at
essentially maximum, so discussions of whether the effect is linear
with distance due either to magic or the proportion of "spherical
shell" that interacts are unnecessary at this point. So ignore
any differences between 2r-d and 2r-sqrt(2)d. Since the filaments are
so close, ignore that each figment might see very slightly more of
the neighboring filaments than the opposite matching filament. How
strong must the Travel effect be compared to the Axis effect? By 55
minutes after starting the second page, the formula is ready. If t is
the Travel effect and a the Axis effect,
(t+a) + (2/sqrt(s))(t-a)
must be safely > 0
(sqrt(2)+1) t must be
safely > (sqrt(2)-1) a
t safely > .1716 a.
I have always assumed the
"charge" effect of Axis Alignment is greater than the
"gravity" effect of Travel Alignment. This ratio may work.
Note I used "safely" since the two simplifying assumptions
assume a little extra stability than would actually be present.
To maintain stability,
each outer filament must stay outside the line between the two
adjacent, opposite type filaments. But pushing a majority of the
whole filament a distance opposed by the Separation effect of the
other three filaments probably takes some doing.
One good aspect of travel
in the same direction means that at velocity v, all figments in the
filaments can have the same angle of travel to centerline,
maintaining inertia as with coils and filaments in general.
Now what form does this
cross section take to become a neutrino? A linear filament would
always move at c and not be quantized and might be hard to recruit
and start, so maybe a ring would be simplest.
The inner two rings may
wobble in their travel and the outer rings not. The inner rings may
be shorter and so rotate a little faster. Or the inner and outer
rings may switch places so that each travels the same distance. I
imagine that usually two filaments would be inside and two outside
rather than having one longest ring and one shortest ring.
Strands Twist
(2012-10-23)
If the filaments could
twist enough that all have the same length, that would be an
improvement. With a little thought and a few sketches, what if the
assembly of 4 filaments twists 180 degrees per ring revolution. That
would lead to two filaments, 1 n and 1 p, the same length, traveling
2 circles or rings. The only difficulty is that at c, the filaments
overlap. They will not be rotating at c (rest mass will be 0) and all
figment motion will be in the direction of travel, so the
discontinuity in filaments may be minor.
Growing filaments is
fairly easy at least in high density regions like the early universe.
Growing the neutrino may not be quite as simple, since getting
opposing filaments to travel or form in the suggested cross section
going the same direction is hard to picture. At rest neutrino type
rings could bend from filaments going opposite directions, but how
that would translate to bent filaments of opposite types going the
same direction is not clear.
I am not entirely happy
with this whole development, but it is feasible. This neutrino game
ain't over 'til its over.
And more of the basic
document needs to be rewritten.
So we have another image
of opposing tendencies leading to stability. Let me add an
exclamation point to that!
With thanks to William Shakespeare, one of the giants of literature,
"And thus by opposing them, conserve them."
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